What is the solution for (dy)/(dt)=t^2(1+15y) ?

The solution for (dy)/(dt)=t^2(1+15y) is y=(e^{5t^3+c_{1}})/(15)-1/15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dt)=t^2(1+15y)

\frac{d y}{d t} = t^{2} (1 + 15 y)

y = \frac{e ^{5 t^{3} + c_{1}}}{15} - \frac{1}{15}

Solution steps

\frac{d y}{d t} = t^{2} (1 + 15 y)

Solve separable ODE:

y = \frac{e ^{5 t^{3} + c_{1}}}{15} - \frac{1}{15}

y = \frac{e ^{5 t^{3} + c_{1}}}{15} - \frac{1}{15}

What is the solution for (dy)/(dt)=t^2(1+15y) ?
The solution for (dy)/(dt)=t^2(1+15y) is y=(e^{5t^3+c_{1}})/(15)-1/15