What is the tangent of f(x)=2sin(x)+1,\at x=-pi/2 ?

The tangent of f(x)=2sin(x)+1,\at x=-pi/2 is y=-1

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tangent of f(x)=2sin(x)+1,\at x=-pi/2

tangent of

f (x) = 2 sin (x) + 1, at x = - \frac{π}{2}

y = - 1

Solution steps

Find the tangent point:

(- \frac{π}{2}, - 1)

Find the slope of

f (x) = 2 sin (x) + 1 : \frac{df ( x )}{d x} = 2 cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(- \frac{π}{2}, - 1) : y = - 1

y = - 1

What is the tangent of f(x)=2sin(x)+1,\at x=-pi/2 ?
The tangent of f(x)=2sin(x)+1,\at x=-pi/2 is y=-1