What is the integral of 1/(x^{1/2)+x^{3/2}} ?

The integral of 1/(x^{1/2)+x^{3/2}} is 2arctan(x^{1/2})+C

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integral of 1/(x^{1/2)+x^{3/2}}

\int \frac{1}{x ^{\frac{1}{2}} + x ^{\frac{3}{2}}} d x

2 arctan (x^{\frac{1}{2}}) + C

Solution steps

\int \frac{1}{x ^{\frac{1}{2}} + x ^{\frac{3}{2}}} d x

Apply u-substitution

= \int \frac{2}{1 + u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{1 + u ^{2}} d u

Use the common integral:

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

= 2 arctan (u)

Substitute back

u = x^{\frac{1}{2}}

= 2 arctan (x^{\frac{1}{2}})

Add a constant to the solution

= 2 arctan (x^{\frac{1}{2}}) + C

What is the integral of 1/(x^{1/2)+x^{3/2}} ?
The integral of 1/(x^{1/2)+x^{3/2}} is 2arctan(x^{1/2})+C