What is the derivative of 2x-3x^{2/3} ?

The derivative of 2x-3x^{2/3} is 2-2/(x^{1/3)}

What is the first derivative of 2x-3x^{2/3} ?

The first derivative of 2x-3x^{2/3} is 2-2/(x^{1/3)}

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\frac{d}{d x} (2 x - 3 x^{\frac{2}{3}})

2 - \frac{2}{x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (2 x - 3 x^{\frac{2}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (3 x^{\frac{2}{3}})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3 x^{\frac{2}{3}}) = \frac{2}{x ^{\frac{1}{3}}}

= 2 - \frac{2}{x ^{\frac{1}{3}}}

What is the derivative of 2x-3x^{2/3} ?
The derivative of 2x-3x^{2/3} is 2-2/(x^{1/3)}
What is the first derivative of 2x-3x^{2/3} ?
The first derivative of 2x-3x^{2/3} is 2-2/(x^{1/3)}