(dy)/(dx)= 2/x

Lösung

\frac{d y}{d x} = \frac{2}{x}

y = 2 ln (x) + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = \frac{2}{x}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = \frac{2}{x}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{2}{x} d x

\int \frac{2}{x} d x = 2 ln (x) + c_{1}

y = 2 ln (x) + c_{1}

\frac{d}{d x} (\frac{a}{1 + \frac{b}{x + c}})

\int 6 x^{2} d x

x \to 0 lim (x - \frac{1}{ln ∣ x ∣})

x^{2} y^{^{'}} + 2 x y = ln (x), y (1) = 6

x \to - 2 - lim (\frac{x}{x ^{2} - 4})