integral of (8x^3-9x^2+4)

Lösung

\int (8 x^{3} - 9 x^{2} + 4) d x

2 x^{4} - 3 x^{3} + 4 x + C

Schritte zur Lösung

\int 8 x^{3} - 9 x^{2} + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{3} d x - \int 9 x^{2} d x + \int 4 d x

\int 8 x^{3} d x = 2 x^{4}

\int 9 x^{2} d x = 3 x^{3}

\int 4 d x = 4 x

= 2 x^{4} - 3 x^{3} + 4 x

Füge eine Konstante zur Lösung hinzu

= 2 x^{4} - 3 x^{3} + 4 x + C