(dy)/(dx)=\sqrt[3]{x}

解答

\frac{d y}{d x} = 3 x

y = \frac{3}{4} x^{\frac{4}{3}} + c_{1}

求解步骤

\frac{d y}{d x} = 3 x

替代

\frac{d y}{d x}

与

y^{'} (x)

y^{^{'}} (x) = 3 x

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

y = \int 3 x d x

\int 3 x d x = \frac{3}{4} x^{\frac{4}{3}} + c_{1}

y = \frac{3}{4} x^{\frac{4}{3}} + c_{1}

\int \frac{1}{( x - 1 ) ( x ^{2} + 1 )} d x

y^{^{''}} - 5 y^{^{'}} - 6 y = 12 e^{2} t

\frac{\partial}{\partial x} (y e^{3 x})

\frac{d}{d x} (- 2 (2 x^{2} - 4 x - 1)^{2})

\frac{\partial}{\partial x} (2)