What is the tangent of f(x)=9x-8sqrt(x),(1,1) ?

The tangent of f(x)=9x-8sqrt(x),(1,1) is y=5x-4

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tangent of f(x)=9x-8sqrt(x),(1,1)

tangent of

f (x) = 9 x - 8 x, (1, 1)

y = 5 x - 4

Solution steps

Find the slope of

f (x) = 9 x - 8 x : \frac{df ( x )}{d x} = 9 - \frac{4}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(1, 1) : y = 5 x - 4

y = 5 x - 4

What is the tangent of f(x)=9x-8sqrt(x),(1,1) ?
The tangent of f(x)=9x-8sqrt(x),(1,1) is y=5x-4