What is the solution for y^'=((3x^7e^{y/x}+x^5y^2))/(x^6y) ?

The solution for y^'=((3x^7e^{y/x}+x^5y^2))/(x^6y) is y=-\W((3ln(x)+c_{1})/e)x-x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=((3x^7e^{y/x}+x^5y^2))/(x^6y)

y^{^{'}} = \frac{( 3 x ^{7} e ^{\frac{y}{x}} + x ^{5} y ^{2} )}{x ^{6} y}

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{( 3 x ^{7} e ^{\frac{y}{x}} + x ^{5} y ^{2} )}{x ^{6} y}

Solve using substitution:

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

What is the solution for y^'=((3x^7e^{y/x}+x^5y^2))/(x^6y) ?
The solution for y^'=((3x^7e^{y/x}+x^5y^2))/(x^6y) is y=-\W((3ln(x)+c_{1})/e)x-x