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Popular Calculus >

y^'=(1-2x)y^2,y(0)=-1/6

Solution

y^{^{'}} = (1 - 2 x) y^{2}, y (0) = - \frac{1}{6}

Solution

y = - \frac{1}{x - x ^{2} + 6}

Solution steps

y^{'} (x) = (1 - 2 x) y^{2}

Solve separable ODE:

y = - \frac{1}{x - x ^{2} + 6}

y = - \frac{1}{x - x ^{2} + 6}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(1-2x)y^2,y(0)=-1/6 ?
The solution for y^'=(1-2x)y^2,y(0)=-1/6 is y=-1/(x-x^2+6)