What is the derivative of x^2cos(xy) ?

The derivative of x^2cos(xy) is 2xcos(xy)-x^2sin(xy)(y+x(dy)/(dx))

What is the first derivative of x^2cos(xy) ?

The first derivative of x^2cos(xy) is 2xcos(xy)-x^2sin(xy)(y+x(dy)/(dx))

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\frac{d}{d x} (x^{2} cos (x y))

2 x cos (x y) - x^{2} sin (x y) (y + x \frac{d y}{d x})

Solution steps

\frac{d}{d x} (x^{2} cos (x y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = cos (x y)

= \frac{d}{d x} (x^{2}) cos (x y) + \frac{d}{d x} (cos (x y)) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (cos (x y)) = - sin (x y) (y + x \frac{d y}{d x})

= 2 x cos (x y) + (- sin (x y) (y + x \frac{d y}{d x})) x^{2}

Simplify

= 2 x cos (x y) - x^{2} sin (x y) (y + x \frac{d y}{d x})

What is the derivative of x^2cos(xy) ?
The derivative of x^2cos(xy) is 2xcos(xy)-x^2sin(xy)(y+x(dy)/(dx))
What is the first derivative of x^2cos(xy) ?
The first derivative of x^2cos(xy) is 2xcos(xy)-x^2sin(xy)(y+x(dy)/(dx))