What is the integral of 4/(sqrt(1-x^2)) ?

The integral of 4/(sqrt(1-x^2)) is 4arcsin(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 4/(sqrt(1-x^2))

\int \frac{4}{1 - x ^{2}} d x

4 arcsin (x) + C

Solution steps

\int \frac{4}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 4 arcsin (x)

Add a constant to the solution

= 4 arcsin (x) + C

What is the integral of 4/(sqrt(1-x^2)) ?
The integral of 4/(sqrt(1-x^2)) is 4arcsin(x)+C