What is the solution for x^2y^'+8xy=17y^3 ?

The solution for x^2y^'+8xy=17y^3 is y=sqrt(x/(2+c_{1)x^{17)}},y=-sqrt(x/(2+c_{1)x^{17)}}

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x^2y^'+8xy=17y^3

x^{2} y^{^{'}} + 8 x y = 17 y^{3}

y = \frac{x}{2 + c _{1} x ^{17}}, y = - \frac{x}{2 + c _{1} x ^{17}}

Solution steps

x^{2} y^{'} (x) + 8 x y = 17 y^{3}

Solve Bernoulli ODE:

y = \frac{x}{2 + c _{1} x ^{17}}, y = - \frac{x}{2 + c _{1} x ^{17}}

y = \frac{x}{2 + c _{1} x ^{17}}, y = - \frac{x}{2 + c _{1} x ^{17}}

What is the solution for x^2y^'+8xy=17y^3 ?
The solution for x^2y^'+8xy=17y^3 is y=sqrt(x/(2+c_{1)x^{17)}},y=-sqrt(x/(2+c_{1)x^{17)}}