What is the tangent of y= 8/(sqrt(x)),(16, 8/4) ?

The tangent of y= 8/(sqrt(x)),(16, 8/4) is y=-1/16 x+3

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tangent of y= 8/(sqrt(x)),(16, 8/4)

tangent of

y = \frac{8}{x}, (16, \frac{8}{4})

y = - \frac{1}{16} x + 3

Solution steps

Find the slope of

y = \frac{8}{x} : \frac{d y}{d x} = - \frac{4}{x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{16}

Find the line with slope m=

- \frac{1}{16}

and passing through

(16, \frac{8}{4}) : y = - \frac{1}{16} x + 3

y = - \frac{1}{16} x + 3

What is the tangent of y= 8/(sqrt(x)),(16, 8/4) ?
The tangent of y= 8/(sqrt(x)),(16, 8/4) is y=-1/16 x+3