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Popular Calculus >

taylor x-1

Solution

taylor

x - 1

Solution

- 1 + x

Solution steps

Apply the Taylor Formula

= - 1 + \frac{\frac{d}{d x} ( x - 1 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x - 1 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x - 1 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= - 1 + \frac{1}{1 !} x + \frac{0}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= - 1 + x

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Frequently Asked Questions (FAQ)

What is taylor x-1 ?
The answer to taylor x-1 is -1+x