What is the solution for (2y^2+4x^2)dx-xydy=0 ?

The solution for (2y^2+4x^2)dx-xydy=0 is y=xsqrt(-4+c_{1)x^2},y=-xsqrt(-4+c_{1)x^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(2y^2+4x^2)dx-xydy=0

(2 y^{2} + 4 x^{2}) d x - x y d y = 0

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

Solution steps

(2 y^{2} + 4 x^{2}) d x - x y d y = 0

Solve Bernoulli ODE:

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

What is the solution for (2y^2+4x^2)dx-xydy=0 ?
The solution for (2y^2+4x^2)dx-xydy=0 is y=xsqrt(-4+c_{1)x^2},y=-xsqrt(-4+c_{1)x^2}