integral from 0 to infinity of sin(4x)

解答

\int_{0}^{\infty} sin (4 x) d x

发散

求解步骤

\int_{0}^{\infty} sin (4 x) d x

计算不定积分:

\int sin (4 x) d x = - \frac{1}{4} cos (4 x) + C

带入上下限计算后得:

\int_{0}^{\infty} sin (4 x) d x =

发散

= 发散

\int \frac{- 9}{x ^{2} + 16} d x

\frac{d ^{2}}{d x ^{2}} ((3 x^{2} + 6 x) sin (x))

\frac{d}{d x} (cos (2 x - 1) tan (1 - 2 x))

a re a e^{x}, x e^{x^{2}}, [0, 1]

d er i v a t i v e f (x) = \frac{1}{( 3 - x ) ^{2}}