x^'= 1/(x^2),x(1)=1

解答

x^{^{'}} = \frac{1}{x ^{2}}, x (1) = 1

x = 3 3 t - 2

求解步骤

x^{'} (t) = \frac{1}{x ^{2}}

求解可分离方程:

x = 3 3 t - 2

x = 3 3 t - 2

d er i v a t i v e y = \frac{1}{a ^{2} - x ^{2}}

\frac{\partial}{\partial x} (e^{\frac{x}{b ( x )}})

t \to 0 lim (\frac{5}{1 + t})

y^{^{''}} - 3 y^{^{'}} = 18 t + 26 sin (2 t)

y^{^{''}} + 16 y = 32 sin (4 t)