What is the tangent of x^2+xy+y^2=3,(1,1) ?

The tangent of x^2+xy+y^2=3,(1,1) is y=-x+2

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tangent of x^2+xy+y^2=3,(1,1)

tangent of

x^{2} + x y + y^{2} = 3, (1, 1)

y = - x + 2

Solution steps

Find the slope of

x^{2} + x y + y^{2} = 3 : \frac{d y}{d x} = \frac{- 2 x - y}{x + 2 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(1, 1) : y = - x + 2

y = - x + 2

What is the tangent of x^2+xy+y^2=3,(1,1) ?
The tangent of x^2+xy+y^2=3,(1,1) is y=-x+2