What is (\partial)/(\partial x)(yx-y-x) ?

The answer to (\partial)/(\partial x)(yx-y-x) is y-1

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(\partial)/(\partial x)(yx-y-x)

\frac{\partial}{\partial x} (y x - y - x)

y - 1

Solution steps

\frac{\partial}{\partial x} (y x - y - x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y x) - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (y x) = y

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x) = 1

= y - 0 - 1

Simplify

= y - 1

What is (\partial)/(\partial x)(yx-y-x) ?
The answer to (\partial)/(\partial x)(yx-y-x) is y-1