What is the solution for 1/(x^7)y^'=15+12y ?

The solution for 1/(x^7)y^'=15+12y is y=(e^{(3x^8+c_{1})/2})/(4)-5/4

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1/(x^7)y^'=15+12y

\frac{1}{x ^{7}} y^{^{'}} = 15 + 12 y

y = \frac{e ^{\frac{3 x ^{8} + c _{1}}{2}}}{4} - \frac{5}{4}

Solution steps

\frac{1}{x ^{7}} y^{'} (x) = 15 + 12 y

Solve separable ODE:

y = \frac{e ^{\frac{3 x ^{8} + c _{1}}{2}}}{4} - \frac{5}{4}

y = \frac{e ^{\frac{3 x ^{8} + c _{1}}{2}}}{4} - \frac{5}{4}

What is the solution for 1/(x^7)y^'=15+12y ?
The solution for 1/(x^7)y^'=15+12y is y=(e^{(3x^8+c_{1})/2})/(4)-5/4