What is the integral of 1/(sqrt(1-x^2)arcsin(x)) ?

The integral of 1/(sqrt(1-x^2)arcsin(x)) is ln|arcsin(x)|+C

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integral of 1/(sqrt(1-x^2)arcsin(x))

\int \frac{1}{1 - x ^{2} arcsin ( x )} d x

ln ∣ arcsin (x) ∣ + C

Solution steps

\int \frac{1}{1 - x ^{2} arcsin ( x )} d x

Apply u-substitution

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = arcsin (x)

= ln ∣ arcsin (x) ∣

Add a constant to the solution

= ln ∣ arcsin (x) ∣ + C

What is the integral of 1/(sqrt(1-x^2)arcsin(x)) ?
The integral of 1/(sqrt(1-x^2)arcsin(x)) is ln|arcsin(x)|+C