What is the derivative of (3x^4+6)/(x^2) ?

The derivative of (3x^4+6)/(x^2) is (6(x^4-2))/(x^3)

What is the first derivative of (3x^4+6)/(x^2) ?

The first derivative of (3x^4+6)/(x^2) is (6(x^4-2))/(x^3)

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derivative of

\frac{3 x ^{4} + 6}{x ^{2}}

\frac{6 ( x ^{4} - 2 )}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{3 x ^{4} + 6}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x ^{4} + 6 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( 3 x ^{4} + 6 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (3 x^{4} + 6) = 12 x^{3}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{12 x ^{3} x ^{2} - 2 x ( 3 x ^{4} + 6 )}{( x ^{2} ) ^{2}}

Simplify

\frac{12 x ^{3} x ^{2} - 2 x ( 3 x ^{4} + 6 )}{( x ^{2} ) ^{2}} : \frac{6 ( x ^{4} - 2 )}{x ^{3}}

= \frac{6 ( x ^{4} - 2 )}{x ^{3}}

What is the derivative of (3x^4+6)/(x^2) ?
The derivative of (3x^4+6)/(x^2) is (6(x^4-2))/(x^3)
What is the first derivative of (3x^4+6)/(x^2) ?
The first derivative of (3x^4+6)/(x^2) is (6(x^4-2))/(x^3)