What is area 1,cos^2(x),[0,pi] ?

The answer to area 1,cos^2(x),[0,pi] is 1/2 ((1*0,pi-1)+1/2 (sin(2[0,pi])-sin(2)))

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area 1,cos^2(x),[0,pi]

area

1, cos^{2} (x), [0, π]

\frac{1}{2} ((1 \cdot 0, π - 1) + \frac{1}{2} (sin (2 [0, π]) - sin (2)))

Solution steps

Apply the area formula:

\int_{1}^{[0, π]} ∣ cos (x) ∣^{2} d x

Solve

\int_{1}^{[0, π]} ∣ cos (x) ∣^{2} d x : \frac{1}{2} ((1 \cdot 0, π - 1) + \frac{1}{2} (sin (2 [0, π]) - sin (2)))

The area is:

= \frac{1}{2} ((1 \cdot 0, π - 1) + \frac{1}{2} (sin (2 [0, π]) - sin (2)))

What is area 1,cos^2(x),[0,pi] ?
The answer to area 1,cos^2(x),[0,pi] is 1/2 ((1*0,pi-1)+1/2 (sin(2[0,pi])-sin(2)))