What is the derivative of x^4+8 ?

The derivative of x^4+8 is 4x^3

What is the first derivative of x^4+8 ?

The first derivative of x^4+8 is 4x^3

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\frac{d}{d x} (x^{4} + 8)

4 x^{3}

Solution steps

\frac{d}{d x} (x^{4} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8) = 0

= 4 x^{3} + 0

Simplify

= 4 x^{3}