What is the solution for (3x+2y+1)dx-(3x+2y-1)dy=0 ?

The solution for (3x+2y+1)dx-(3x+2y-1)dy=0 is y=-(2\W(1/(4e^{(25x+c_{1))/4}})-3)/(5)-(3x)/2-1/2

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(3x+2y+1)dx-(3x+2y-1)dy=0

(3 x + 2 y + 1) d x - (3 x + 2 y - 1) d y = 0

y = - \frac{2 W ( \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2} - \frac{1}{2}

Solution steps

(3 x + 2 y + 1) d x - (3 x + 2 y - 1) d y = 0

Solve using substitution:

y = - \frac{2 W ( \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2} - \frac{1}{2}

y = - \frac{2 W ( \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2} - \frac{1}{2}

What is the solution for (3x+2y+1)dx-(3x+2y-1)dy=0 ?
The solution for (3x+2y+1)dx-(3x+2y-1)dy=0 is y=-(2\W(1/(4e^{(25x+c_{1))/4}})-3)/(5)-(3x)/2-1/2