What is the solution for (dy)/(dx)=(x+y+1)^2-(x+y-1)^2 ?

The solution for (dy)/(dx)=(x+y+1)^2-(x+y-1)^2 is y=-x-1/4+c_{1}e^{4x}

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(dy)/(dx)=(x+y+1)^2-(x+y-1)^2

\frac{d y}{d x} = (x + y + 1)^{2} - (x + y - 1)^{2}

y = - x - \frac{1}{4} + c_{1} e^{4 x}

Solution steps

\frac{d y}{d x} = (x + y + 1)^{2} - (x + y - 1)^{2}

Solve linear ODE:

y = - x - \frac{1}{4} + c_{1} e^{4 x}

y = - x - \frac{1}{4} + c_{1} e^{4 x}

What is the solution for (dy)/(dx)=(x+y+1)^2-(x+y-1)^2 ?
The solution for (dy)/(dx)=(x+y+1)^2-(x+y-1)^2 is y=-x-1/4+c_{1}e^{4x}