What is the tangent of (6x)/(sqrt(4-x^2)),\at x=0 ?

The tangent of (6x)/(sqrt(4-x^2)),\at x=0 is y=3x

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tangent of (6x)/(sqrt(4-x^2)),\at x=0

tangent of

\frac{6 x}{4 - x ^{2}}, at x = 0

y = 3 x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

y = \frac{6 x}{4 - x ^{2}} : \frac{d y}{d x} = \frac{24}{( 4 - x ^{2} ) 4 - x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(0, 0) : y = 3 x

y = 3 x

What is the tangent of (6x)/(sqrt(4-x^2)),\at x=0 ?
The tangent of (6x)/(sqrt(4-x^2)),\at x=0 is y=3x