What is the tangent of y=x^2-3x-2,(2,-4) ?

The tangent of y=x^2-3x-2,(2,-4) is y=x-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y=x^2-3x-2,(2,-4)

tangent of

y = x^{2} - 3 x - 2, (2, - 4)

y = x - 6

Solution steps

Find the slope of

y = x^{2} - 3 x - 2 : \frac{d y}{d x} = 2 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(2, - 4) : y = x - 6

y = x - 6

What is the tangent of y=x^2-3x-2,(2,-4) ?
The tangent of y=x^2-3x-2,(2,-4) is y=x-6