What is the solution for xy^'+2y=6x^2sqrt(y) ?

The solution for xy^'+2y=6x^2sqrt(y) is y=x^4+2c_{1}x+(c_{1}^2)/(x^2)

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xy^'+2y=6x^2sqrt(y)

x y^{^{'}} + 2 y = 6 x^{2} y

y = x^{4} + 2 c_{1} x + \frac{c _{1}^{2}}{x ^{2}}

Solution steps

x y^{'} (x) + 2 y = 6 x^{2} y

Solve Bernoulli ODE:

y = x^{4} + 2 c_{1} x + \frac{c _{1}^{2}}{x ^{2}}

y = x^{4} + 2 c_{1} x + \frac{c _{1}^{2}}{x ^{2}}

What is the solution for xy^'+2y=6x^2sqrt(y) ?
The solution for xy^'+2y=6x^2sqrt(y) is y=x^4+2c_{1}x+(c_{1}^2)/(x^2)