What is area sec^2(x),8cos(x) ?

The answer to area sec^2(x),8cos(x) is 6sqrt(3)

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area sec^2(x),8cos(x)

area

sec^{2} (x), 8 cos (x)

63

Decimal

10.39230 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) - 8 cos (x) d x

Solve

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) - 8 cos (x) d x : 63

The area is:

= 63