What is the derivative of sin(3x+cos(4x)) ?

The derivative of sin(3x+cos(4x)) is cos(3x)*3-sin(4x)*4

What is the first derivative of sin(3x+cos(4x)) ?

The first derivative of sin(3x+cos(4x)) is cos(3x)*3-sin(4x)*4

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\frac{d}{d x} (sin (3 x) + cos (4 x))

cos (3 x) \cdot 3 - sin (4 x) \cdot 4

Solution steps

\frac{d}{d x} (sin (3 x) + cos (4 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (3 x)) + \frac{d}{d x} (cos (4 x))

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

\frac{d}{d x} (cos (4 x)) = - sin (4 x) \cdot 4

= cos (3 x) \cdot 3 - sin (4 x) \cdot 4

What is the derivative of sin(3x+cos(4x)) ?
The derivative of sin(3x+cos(4x)) is cos(3x)*3-sin(4x)*4
What is the first derivative of sin(3x+cos(4x)) ?
The first derivative of sin(3x+cos(4x)) is cos(3x)*3-sin(4x)*4