What is area y=x^3,y=x^2-2x,[0,1] ?

The answer to area y=x^3,y=x^2-2x,[0,1] is 11/12

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area y=x^3,y=x^2-2x,[0,1]

area

y = x^{3}, y = x^{2} - 2 x, [0, 1]

\frac{11}{12}

Decimal

0.91666 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x^{3} - (x^{2} - 2 x) d x

Solve

\int_{0}^{1} x^{3} - (x^{2} - 2 x) d x : \frac{11}{12}

The area is:

= \frac{11}{12}

What is area y=x^3,y=x^2-2x,[0,1] ?
The answer to area y=x^3,y=x^2-2x,[0,1] is 11/12