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Popular Calculus >

y^'+3y+5=0

Solution

y^{^{'}} + 3 y + 5 = 0

Solution

y = \frac{e ^{- 3 t - c_{1}}}{3} - \frac{5}{3}

Solution steps

y^{'} (t) + 3 y + 5 = 0

Solve separable ODE:

y = \frac{e ^{- 3 t - c_{1}}}{3} - \frac{5}{3}

y = \frac{e ^{- 3 t - c_{1}}}{3} - \frac{5}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+3y+5=0 ?
The solution for y^'+3y+5=0 is y=(e^{-3t-c_{1}})/3-5/3