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Popular Calculus >

y^'=2t

Solution

y^{^{'}} = 2 t

Solution

y = t^{2} + c_{1}

Solution steps

y^{'} (t) = 2 t

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 2 t d t

\int 2 t d t = t^{2} + c_{1}

y = t^{2} + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=2t ?
The solution for y^'=2t is y=t^2+c_{1}