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Popular Calculus >

integral of-1(x-4)

Solution

\int - 1 (x - 4) d x

Solution

- \frac{x ^{2}}{2} + 4 x + C

Solution steps

\int - 1 \cdot (x - 4) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (\int x d x - \int 4 d x)

\int x d x = \frac{x ^{2}}{2}

\int 4 d x = 4 x

= - (\frac{x ^{2}}{2} - 4 x)

Simplify

= - \frac{x ^{2}}{2} + 4 x

Add a constant to the solution

= - \frac{x ^{2}}{2} + 4 x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of-1(x-4) ?
The integral of-1(x-4) is -(x^2)/2+4x+C