What is the solution for (dx)/(dt)=0.8x-0.004x^2 ?

The solution for (dx)/(dt)=0.8x-0.004x^2 is x=(200}{-250e^{\frac{-c_{1}-4t)/5}+1}

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(dx)/(dt)=0.8x-0.004x^2

\frac{d x}{d t} = 0.8 x - 0.004 x^{2}

x = \frac{200}{- 250 e ^{\frac{- c _{1} - 4 t}{5}} + 1}

Solution steps

\frac{d x}{d t} = 0.8 x - 0.004 x^{2}

Solve Bernoulli ODE:

x = \frac{200}{- 250 e ^{\frac{- c _{1} - 4 t}{5}} + 1}

x = \frac{200}{- 250 e ^{\frac{- c _{1} - 4 t}{5}} + 1}

What is the solution for (dx)/(dt)=0.8x-0.004x^2 ?
The solution for (dx)/(dt)=0.8x-0.004x^2 is x=(200}{-250e^{\frac{-c_{1}-4t)/5}+1}