What is the derivative of \sqrt[7]{3x-1} ?

The derivative of \sqrt[7]{3x-1} is 3/(7(3x-1)^{6/7)}

What is the first derivative of \sqrt[7]{3x-1} ?

The first derivative of \sqrt[7]{3x-1} is 3/(7(3x-1)^{6/7)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{3}{7 ( 3 x - 1 ) ^{\frac{6}{7}}}

Solution steps

Apply the chain rule:

\frac{1}{7 ( 3 x - 1 ) ^{\frac{6}{7}}} \frac{d}{d x} (3 x - 1)

= \frac{1}{7 ( 3 x - 1 ) ^{\frac{6}{7}}} \frac{d}{d x} (3 x - 1)

\frac{d}{d x} (3 x - 1) = 3

= \frac{1}{7 ( 3 x - 1 ) ^{\frac{6}{7}}} \cdot 3

Simplify

\frac{1}{7 ( 3 x - 1 ) ^{\frac{6}{7}}} \cdot 3 : \frac{3}{7 ( 3 x - 1 ) ^{\frac{6}{7}}}

= \frac{3}{7 ( 3 x - 1 ) ^{\frac{6}{7}}}

What is the derivative of \sqrt[7]{3x-1} ?
The derivative of \sqrt[7]{3x-1} is 3/(7(3x-1)^{6/7)}
What is the first derivative of \sqrt[7]{3x-1} ?
The first derivative of \sqrt[7]{3x-1} is 3/(7(3x-1)^{6/7)}