What is area y= 4/(sqrt(4-x^2)),(0,1) ?

The answer to area y= 4/(sqrt(4-x^2)),(0,1) is (2pi)/3

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area y= 4/(sqrt(4-x^2)),(0,1)

area

y = \frac{4}{4 - x ^{2}}, (0, 1)

\frac{2 π}{3}

Decimal

2.09439 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} \frac{4}{4 - x ^{2}} d x

Solve

\int_{0}^{1} \frac{4}{4 - x ^{2}} d x : \frac{2 π}{3}

The area is:

= \frac{2 π}{3}

What is area y= 4/(sqrt(4-x^2)),(0,1) ?
The answer to area y= 4/(sqrt(4-x^2)),(0,1) is (2pi)/3