What is the solution for (dy)/(dx)=10+40x+10y+40xy ?

The solution for (dy)/(dx)=10+40x+10y+40xy is y=-1+c_{1}e^{10(2x^2+x)}

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(dy)/(dx)=10+40x+10y+40xy

\frac{d y}{d x} = 10 + 40 x + 10 y + 40 x y

y = - 1 + c_{1} e^{10 (2 x^{2} + x)}

Solution steps

\frac{d y}{d x} = 10 + 40 x + 10 y + 40 x y

Solve linear ODE:

y = - 1 + c_{1} e^{10 (2 x^{2} + x)}

y = - 1 + c_{1} e^{10 (2 x^{2} + x)}

What is the solution for (dy)/(dx)=10+40x+10y+40xy ?
The solution for (dy)/(dx)=10+40x+10y+40xy is y=-1+c_{1}e^{10(2x^2+x)}