What is the solution for x(dy)/(dx)+y=y^2x^2ln(x) ?

The solution for x(dy)/(dx)+y=y^2x^2ln(x) is y= 1/(x(-xln(x)+x+c_{1))}

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x(dy)/(dx)+y=y^2x^2ln(x)

x \frac{d y}{d x} + y = y^{2} x^{2} ln (x)

y = \frac{1}{x ( - x ln ( x ) + x + c _{1} )}

Solution steps

x \frac{d y}{d x} + y = y^{2} x^{2} ln (x)

Solve Bernoulli ODE:

y = \frac{1}{x ( - x ln ( x ) + x + c _{1} )}

y = \frac{1}{x ( - x ln ( x ) + x + c _{1} )}

What is the solution for x(dy)/(dx)+y=y^2x^2ln(x) ?
The solution for x(dy)/(dx)+y=y^2x^2ln(x) is y= 1/(x(-xln(x)+x+c_{1))}