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Popular Calculus >

integral of 16e^x

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Solution

∫16exdx

Solution

16ex+C
Solution steps
∫16exdx
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=16⋅∫exdx
Use the common integral: ∫exdx=ex=16ex
Add a constant to the solution=16ex+C

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derivative of (f(x))/(x^2+8)(dx)/(dt)=0.3*10-x/(40)derivative of csc^2(θ)-4derivative of h(x)= 1/(x^2+4x-21)integral of (sqrt(x)+1/(x^4))

Frequently Asked Questions (FAQ)

  • What is the integral of 16e^x ?

    The integral of 16e^x is 16e^x+C
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