What is area y=x^4+x^3,y=x^4+x^2+6x ?

The answer to area y=x^4+x^3,y=x^4+x^2+6x is 253/12

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area y=x^4+x^3,y=x^4+x^2+6x

area

y = x^{4} + x^{3}, y = x^{4} + x^{2} + 6 x

\frac{253}{12}

Decimal

21.08333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{4} + x^{3} - (x^{4} + x^{2} + 6 x) d x

Solve

\int_{- 2}^{3} x^{4} + x^{3} - (x^{4} + x^{2} + 6 x) d x : \frac{253}{12}

The area is:

= \frac{253}{12}

What is area y=x^4+x^3,y=x^4+x^2+6x ?
The answer to area y=x^4+x^3,y=x^4+x^2+6x is 253/12