What is the tangent of f(x)=(10x)/(1+x^2),(3,3) ?

The tangent of f(x)=(10x)/(1+x^2),(3,3) is y=-4/5 x+27/5

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tangent of f(x)=(10x)/(1+x^2),(3,3)

tangent of

f (x) = \frac{10 x}{1 + x ^{2}}, (3, 3)

y = - \frac{4}{5} x + \frac{27}{5}

Solution steps

Find the slope of

f (x) = \frac{10 x}{1 + x ^{2}} : \frac{df ( x )}{d x} = \frac{10 ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{4}{5}

Find the line with slope m=

- \frac{4}{5}

and passing through

(3, 3) : y = - \frac{4}{5} x + \frac{27}{5}

y = - \frac{4}{5} x + \frac{27}{5}

What is the tangent of f(x)=(10x)/(1+x^2),(3,3) ?
The tangent of f(x)=(10x)/(1+x^2),(3,3) is y=-4/5 x+27/5