What is the derivative of (3x-2/(2x+1)) ?

The derivative of (3x-2/(2x+1)) is 7/((2x+1)^2)

What is the first derivative of (3x-2/(2x+1)) ?

The first derivative of (3x-2/(2x+1)) is 7/((2x+1)^2)

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\frac{d}{d x} (\frac{3 x - 2}{2 x + 1})

\frac{7}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x - 2}{2 x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x - 2 ) ( 2 x + 1 ) - \frac{d}{d x} ( 2 x + 1 ) ( 3 x - 2 )}{( 2 x + 1 ) ^{2}}

\frac{d}{d x} (3 x - 2) = 3

\frac{d}{d x} (2 x + 1) = 2

= \frac{3 ( 2 x + 1 ) - 2 ( 3 x - 2 )}{( 2 x + 1 ) ^{2}}

Expand

3 (2 x + 1) - 2 (3 x - 2) : 7

= \frac{7}{( 2 x + 1 ) ^{2}}

What is the derivative of (3x-2/(2x+1)) ?
The derivative of (3x-2/(2x+1)) is 7/((2x+1)^2)
What is the first derivative of (3x-2/(2x+1)) ?
The first derivative of (3x-2/(2x+1)) is 7/((2x+1)^2)