What is the tangent of f(x)=-3x^{2/3},\at x=-8 ?

The tangent of f(x)=-3x^{2/3},\at x=-8 is y=-1/((-1)^{1/3)}x-4

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tangent of f(x)=-3x^{2/3},\at x=-8

tangent of

f (x) = - 3 x^{\frac{2}{3}}, at x = - 8

y = - \frac{1}{( - 1 ) ^{\frac{1}{3}}} x - 4

Solution steps

Find the tangent point:

(- 8, - 12)

Find the slope of

f (x) = - 3 x^{\frac{2}{3}} : \frac{df ( x )}{d x} = - \frac{2}{x ^{\frac{1}{3}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{( - 1 ) ^{\frac{1}{3}}}

Find the line with slope m=

- \frac{1}{( - 1 ) ^{\frac{1}{3}}}

and passing through

(- 8, - 12) : y = - \frac{1}{( - 1 ) ^{\frac{1}{3}}} x - 4

y = - \frac{1}{( - 1 ) ^{\frac{1}{3}}} x - 4

What is the tangent of f(x)=-3x^{2/3},\at x=-8 ?
The tangent of f(x)=-3x^{2/3},\at x=-8 is y=-1/((-1)^{1/3)}x-4