What is the derivative of-2x^5+1/(2x^2) ?

The derivative of-2x^5+1/(2x^2) is -10x^4-1/(x^3)

What is the first derivative of-2x^5+1/(2x^2) ?

The first derivative of-2x^5+1/(2x^2) is -10x^4-1/(x^3)

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\frac{d}{d x} (- 2 x^{5} + \frac{1}{2 x ^{2}})

- 10 x^{4} - \frac{1}{x ^{3}}

Solution steps

\frac{d}{d x} (- 2 x^{5} + \frac{1}{2 x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{5}) + \frac{d}{d x} (\frac{1}{2 x ^{2}})

\frac{d}{d x} (2 x^{5}) = 10 x^{4}

\frac{d}{d x} (\frac{1}{2 x ^{2}}) = - \frac{1}{x ^{3}}

= - 10 x^{4} - \frac{1}{x ^{3}}

What is the derivative of-2x^5+1/(2x^2) ?
The derivative of-2x^5+1/(2x^2) is -10x^4-1/(x^3)
What is the first derivative of-2x^5+1/(2x^2) ?
The first derivative of-2x^5+1/(2x^2) is -10x^4-1/(x^3)