What is the derivative of (x-3)(x+2)(x+3) ?

The derivative of (x-3)(x+2)(x+3) is 3x^2+4x-9

What is the first derivative of (x-3)(x+2)(x+3) ?

The first derivative of (x-3)(x+2)(x+3) is 3x^2+4x-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

(x - 3) (x + 2) (x + 3)

3 x^{2} + 4 x - 9

Solution steps

\frac{d}{d x} ((x - 3) (x + 2) (x + 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - 3, g = (x + 2) (x + 3)

= \frac{d}{d x} (x - 3) (x + 2) (x + 3) + \frac{d}{d x} ((x + 2) (x + 3)) (x - 3)

\frac{d}{d x} (x - 3) = 1

\frac{d}{d x} ((x + 2) (x + 3)) = 2 x + 5

= 1 \cdot (x + 2) (x + 3) + (2 x + 5) (x - 3)

Simplify

1 \cdot (x + 2) (x + 3) + (2 x + 5) (x - 3) : 3 x^{2} + 4 x - 9

= 3 x^{2} + 4 x - 9

What is the derivative of (x-3)(x+2)(x+3) ?
The derivative of (x-3)(x+2)(x+3) is 3x^2+4x-9
What is the first derivative of (x-3)(x+2)(x+3) ?
The first derivative of (x-3)(x+2)(x+3) is 3x^2+4x-9