What is the integral of 2sin(x)+9 ?

The integral of 2sin(x)+9 is -2cos(x)+9x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 2sin(x)+9

\int 2 sin (x) + 9 d x

- 2 cos (x) + 9 x + C

Solution steps

\int 2 sin (x) + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 sin (x) d x + \int 9 d x

\int 2 sin (x) d x = - 2 cos (x)

\int 9 d x = 9 x

= - 2 cos (x) + 9 x

Add a constant to the solution

= - 2 cos (x) + 9 x + C