What is the integral of ((x+6)/(sqrt(x))) ?

The integral of ((x+6)/(sqrt(x))) is 2/3 x^{3/2}+12sqrt(x)+C

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integral of ((x+6)/(sqrt(x)))

\int (\frac{x + 6}{x}) d x

\frac{2}{3} x^{\frac{3}{2}} + 12 x + C

Solution steps

\int \frac{x + 6}{x} d x

Expand

\frac{x + 6}{x} : x + \frac{6}{x}

= \int x + \frac{6}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int \frac{6}{x} d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int \frac{6}{x} d x = 12 x

= \frac{2}{3} x^{\frac{3}{2}} + 12 x

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + 12 x + C

What is the integral of ((x+6)/(sqrt(x))) ?
The integral of ((x+6)/(sqrt(x))) is 2/3 x^{3/2}+12sqrt(x)+C